January 09, 2025

Detailed explanation of the pin diagram of the microcontroller chip 74HC595

14-pin: DS(SER), serial data input pin

13 pin: OE, %20 output enable control pin, it is low-power to enable output, so connect to GND

12-pin: RCK, storage register clock input pin. On the rising edge, data is transferred from the shift register to the storage register.

11 Pin: SCK, shift register clock pin. When the rising edge shifts, the bit %20 data in the shift register is shifted back and the new bit is accepted (input from SER).

10 feet: MR, when the low level, clear the bit data that already exists in the shift register, generally do not need, accept %20 high level then.

9%20 foot %20: serial data exit pin. When the data in the shift register is more than 8 bits, the existing bit will be "squeezed out" and it is going out from here. Used for the 595 cascade.

Qx: Parallel output pin

The use of parameters VCC: 2V ~ 6V, 5V is best

I%20Qn: +-%2035mA

Note that the first bit sent from SER will go out from Q7.

74HC595 introduces a picture and a piece of text, which kind of information transmission way gives the person the first visual impact is the biggest? I think everybody has the answer in the heart.

This is also the reason for the title of my article. Nonsense is here, I will use the picture below to analyze the 595 chip.

The 74HC595's most important function is: serial input, parallel output. 3-state high-speed shift register (good to say)

595 has two 8-bit registers: shift register, storage register

Shift Register

In my opinion, the 74HC595's shift register works like a shou%20%20qiang clip. But the launch of the bullet (data in the shift register is dumped into the storage register), it is also like a bullet (because it is parallel output)

Why is it like a clip?

1, serial input, the bit data has been entered in turn (so called shift register)% 20 |% 20 bullets are also a one on the first bullet, after being pressed down slowly.

2. The first input bit is the last bit in the parallel output %20|%20 that first entered the magazine's bullet and finally fired.

Pinout for 74HC595

14 feet: DS, also called SER English full name is: Serial data input, as the name implies, is the serial data input port.

The data source of 595 is only this one mouth, can only input a bit at a time, then input 8 times continuously, can accumulate into one byte.

If we want to input the binary data 0111 1111 to the shift register of 595, let's take a dynamic picture to simulate the scene of the first 2 bits input.

There are 7 frames in this picture. It has been done for a long time. After all, it is not an artist. It can be said that there are specializations in the field of surgery, there are successive ah, you still want to learn humbly :)

0111 1111 This data is completely input like this

We must also pay attention to a foot: 11 feet, shift register clock input shift register clock pin. The rising edge is valid.

First of all, we have to introduce the role of this pin.

We know that the work of the 51 single-chip microcomputer is inseparable from the crystal oscillator. He makes the CPU work in a stable and orderly manner, just like the one who called 1,2,1 while running.

The shift register clock here is also the same reason. When a new bit data comes in, the already entered bit data is shifted backwards and out of position under the control of the clock pulse of the shift register.

Rising edge: The process from low to high. The shift register clock is only active during the rising edge of this process.

Storage register

Here we have roughly talked about how to get a bullet and put the bullets together. Here's how to fire the bullet, which is how to shift the data of the shift register to the storage register

The storage register is directly connected to the 8 output pins. After shifting the data of the shift register to the storage register, Q0 Q1 Q2 Q3 Q4 Q5 Q6 Q7 can be accepted to us.

Start inputting one byte of data. The so-called storage register, the data can exist in this register, and will not disappear with an output, as long as the 595 is off, there is no new

The data comes from the shift register and the data remains constant and valid. After the new data comes, the data in the storage register will be overwritten and updated.

12 feet: (storage register clock input) storage register clock

Data is transferred from the shift register to the storage register, which also needs the clock pulse. This is the role of the 12-pin. It is also valid for rising edges.

Since then, we have explained a 595 normal workflow

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